在JSP开发过程中,经常需要根据不同的业务逻辑进行页面跳转。以下是一个简单的实例,展示如何通过Action进行页面跳转。
项目结构:

```
-- webapps
-- myapp
-- WEB-INF
-- views
-- success.jsp
-- failure.jsp
-- actions
-- MyAction.java
-- web.xml
```
1. 创建Action类(MyAction.java):
```java
package actions;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
public class MyAction extends Action {
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException {
// 根据业务逻辑判断是否跳转
boolean isSuccess = true; // 假设业务逻辑处理成功
if (isSuccess) {
return mapping.findForward("







